So 19 points isn’t 2d10-1, but rather 2d8+3. When converting max damage to dice, I always use the largest dice I can, but don’t allow subtraction. Given the energy involved, that’s probably as good as the d20 modern values. But setting A=4 and B= 5 is actually better at fitting the BMG, and puts the. Solver gave an exact figure of A = 3.88 and B of 5.1. 50BMG, which assumes a man-portable 32″ barrel instead of the 43″ bbl on the machinegun (which is about 16,000J). That was to force Solver (in Excel) to give more weight to making the. 22LR got 1000x the figured sum, the 9mm got 4000x, and the BMG got 9000x. I squared the difference and normalized it to the target squared. I used a formula to set a quantity of D = A * logB(Energy). Fine – acknowledged it’s not perfect, but it’s a scale that actually fits reasonably well with d20 Modern and can be extrapolated to other weapons.
Now, this is totally based on energy, and that means the big, slow bullets are worse than small fast ones. It compresses the scale even further than the usual result, but it’s not insane. I whipped out solver, and it turns out if you use the energy of the bullet, and only the energy of the bullet, if you use 4 * Log (Base 5) Energy you get a number that might just equate to the maximum damage you can roll on the dice. Why would I ever do such a thing? I had noted (complained, really) that a 9mm was 2d6, and the mighty. I wondered to myself if there was a way to turn some sort of real-world number into D&D damage output. But I was thinking, probably because of my comments in my firearms-related Violent Resolution column.īut.
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